-16t^2+8t+80t=0

Solution for -16t^2+8t+80t=0 equation:

-16t^2+8t+80t=0

We add all the numbers together, and all the variables

-16t^2+88t=0

a = -16; b = 88; c = 0;
Δ = b2-4ac
Δ = 882-4·(-16)·0
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7744}=88$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(88)-88}{2*-16}=\frac{-176}{-32}
=5+1/2
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(88)+88}{2*-16}=\frac{0}{-32}
=0
$